Question

Arrange the following polymers in increasing order of intermolecular forces:

• A. II < III < I
• B. III < II < I
• C. II < I < III
• D. II < III < I

Hint:

Check for hydrogen bonding, polar groups, and aromatic rings to compare intermolecular forces in polymers.

Answer 1

The Correct Option is C

Polymers with phenyl groups have strongest Van der Waals forces due to bulky aromatic rings. Ester linkages allow moderate hydrogen bonding. C=C polymer has weakest intermolecular forces. Hence II < I < III.