Question:

Arrange the following number of teams in a sequential order from less to more with respect to allotment of
byes in a Knock-out Tournament :
(A) 05 (B) 14
(C) 32   (D) 12
(E) 63
Choose the correct answer from the options given below :

Updated On: Mar 27, 2025
  • (C), (E), (B), (A), (D)
  • (E), (C), (B), (D), (A)
  • (C), (A), (D), (B), (E)
  • (E), (B), (C), (A), (D)
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The Correct Option is A

Approach Solution - 1

The correct order is based on the number of byes required for each team count: 32, 63, 14, 5, and 12.
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Approach Solution -2

The correct order for the number of byes required in a knockout tournament is based on the number of teams and the next highest power of 2. The goal is to ensure that the number of teams is adjusted to be a power of 2 for each round. The number of byes is calculated by subtracting the number of teams from the next power of 2. Here's the breakdown:

32 teams – No byes are required, as 32 is already a power of 2. This ensures a balanced competition with no need for automatic advances.

63 teams – The next highest power of 2 is 64, so 1 bye is needed to make the number of teams even for the first round.

14 teams – The next highest power of 2 is 16, so 2 byes are required to make the number of teams a power of 2.

5 teams – The next highest power of 2 is 8, so 3 byes are needed to make the number of teams even.

12 teams – The next highest power of 2 is 16, so 4 byes are required to ensure a balanced tournament structure.

This system of calculating byes ensures that each subsequent round can proceed with an even number of teams, maintaining a fair competition structure.
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