Question:

Arrange the following in decreasing order of their basicity: 

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In amines, electron-donating groups (like -CH₃) increase basicity, while electron-withdrawing groups (like -NO₂) decrease it.
Updated On: May 16, 2025
  • \( B>C>A \)
  • \( B>A>C \)
  • \( A>B>C \)
  • \( A>C>B \)
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The Correct Option is B

Approach Solution - 1

The basicity of amines depends on the availability of the nitrogen lone pair for protonation. The following factors affect the basicity:
- Methylamine (B): Methyl groups are electron-donating via inductive effects, which increase the electron density on nitrogen, making it more basic.
- Aniline (A): The phenyl group in aniline withdraws electron density from the nitrogen via resonance, making it less basic than methylamine.
- Nitroaniline (C): The nitro group (-NO_2) is a strong electron-withdrawing group. It pulls electron density from the nitrogen through resonance, significantly decreasing its basicity.
Thus, the order of basicity is \( B>A>C \), and the correct answer is option (2).
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Approach Solution -2

The basicity of a compound is determined by its ability to donate a lone pair of electrons to a proton (H+). In the context of organic compounds, the availability of the lone pair on the nitrogen atom largely affects this property. Here is how we evaluate the basicity of the given options:

1. Factors affecting basicity:

The basicity of an amine depends on:

  • Electron donating or withdrawing effects : Groups that donate electrons by +I (inductive) effect increase basicity, while electron withdrawing groups decrease it.
  • Resonance effect: When the lone pair on nitrogen is delocalized through resonance with other atoms, basicity is reduced.

2. Analysis of given options:

  • Compound A: The nitrogen's lone pair may be involved in resonance with an aromatic ring, reducing its availability for protonation and thus its basicity.
  • Compound B: It likely has a strong +I effect without involvement in resonance, making its nitrogen's lone pair readily available.
  • Compound C: If it contains structures leading to significant delocalization of the lone pair, its basicity is reduced similar to compound A.

3. Ordering of basicity:

Considering the above factors, Compound B has the highest basicity as its lone pair is most available. Compound A is less basic than B but more basic than C due to its lesser extent of resonance involvement compared to C. Therefore, the decreasing order of basicity is B > A > C.

Thus, the correct option is:

B>A>C
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