Question:
Arrange the following elements in increasing order of first ionization enthalpy:
Li, Be, B, C, N
Choose the correct answer from the options given below:
Arrange the following elements in increasing order of first ionization enthalpy:
Li, Be, B, C, N
Choose the correct answer from the options given below:
Li, Be, B, C, N
Choose the correct answer from the options given below:
Updated On: Dec 4, 2024
- Li < Be < B < C < N
- Li < B < Be < C < N
- Li < Be < C < B < N
- Li < Be < N < B < C
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
1. Ionization enthalpy increases across a period due to increased nuclear charge.
2. The anomaly: B \(<\) Be because Be has a fully filled $2s^2$ configuration, making it more stable.
3. Final order: Li \(<\) B \(<\) Be \(<\) C \(<\) N.
Was this answer helpful?
5
0
Top Questions on Enthalpy change
- Identify the incorrect statement from the following:
- NEET (UG) - 2024
- Chemistry
- Enthalpy change
- A transition metal 'M' among Sc, Ti, V , Cr, Mn and Fe has the highest second ionisation enthalpy. The spin only magnetic moment value of M+
ion is ______ BM (Near integer) (Given atomic number Sc : 21, Ti : 22, V : 23, Cr : 24, Mn : 25, Fe : 26)- JEE Main - 2024
- Chemistry
- Enthalpy change
- $\Delta_{vap}H^\circ$ for water is $+40.49 \, \text{kJ mol}^{-1}$ at 1 bar and $100^\circ\text{C}$. Change in internal energy for this vaporisation under same condition is .............. kJ mol$^{-1}$. (Integer answer)
(Given R = 8.3 J K$^{-1}$ mol$^{-1}$)- JEE Main - 2024
- Chemistry
- Enthalpy change
- When equal volume of 1M HCl and 1M H$_2$SO$_4$ are separately neutralized by excess volume of 1M NaOH solution, X and Y kJ of heat is liberated respectively. The value of Y/X is ____.
- JEE Main - 2024
- Chemistry
- Enthalpy change
- $\text{Two reactions are given below:}$ \[ 2\text{Fe}_{(s)} + \frac{3}{2}\text{O}_{2(g)} \rightarrow \text{Fe}_2\text{O}_{3(s)}, \Delta H^\circ = -822 \, \text{kJ/mol} \] \[ \text{C}_{(s)} + \frac{1}{2}\text{O}_{2(g)} \rightarrow \text{CO}_{(g)}, \Delta H^\circ = -110 \, \text{kJ/mol} \] $\text{Then enthalpy change for the following reaction}$ \[ 3\text{C}_{(s)} + \text{Fe}_2\text{O}_{3(s)} \rightarrow 2\text{Fe}_{(s)} + 3\text{CO}_{(g)} \]
- JEE Main - 2024
- Chemistry
- Enthalpy change
View More Questions
Questions Asked in NEET exam
- Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : The potential (V) at any axial point, at 2 m distance(r) from the centre of the dipole of dipole moment vector \(\vec{P}\) of magnitude, 4 × 10-6 C m, is ± 9 × 103 V.
(Take \(\frac{1}{4\pi\epsilon_0}=9\times10^9\) SI units)
Reason R : \(V=±\frac{2P}{4\pi \epsilon_0r^2}\), where r is the distance of any axial point, situated at 2 m from the centre of the dipole.
In the light of the above statements, choose the correct answer from the options given below :- NEET (UG) - 2024
- Magnetic Field
- Given below are two statements:
Statement I: Mitochondria and chloroplasts both double membranes bound organelles.
Statement II: Inner membrane of mitochondria is relatively less permeable, as compared chloroplast. I
In the light of the above statements, choose the mis appropriate answer from the options given below- NEET (UG) - 2024
- Cell structure and organelles
- Match List I with List II:Choose the correct answer from the options given below:
List I
List II
A Mesozoic Era I Lower invertebrates B Proterozoic Era II Fish & Amphibia C Cenozoic Era III Birds & Reptiles D Paleozoic Era IV Mammals - NEET (UG) - 2024
- Origin Of Life
- A parallel plate capacitor is charged by connecting it to a battery through a resistor. If I is the current in the circuit, then in the gap between the plates :
- NEET (UG) - 2024
- Capacitors and Capacitance
- The terminal voltage of the battery, whose emf is\(10V\) and internal resistance \(1\), when connected through an external resistance of \(42\) as shown in the figure is:
- NEET (UG) - 2024
- Resistance and Resistivity
View More Questions