Step 1: The area of the circle is equal to the area of the square. The area of the square is given by: \[ \text{Area of square} = \text{side}^2 = 10^2 = 100 \, \text{cm}^2. \] Step 2: The area of the circle is \( \pi r^2 \), where \( r \) is the radius. Thus, we can equate the area of the circle to the area of the square: \[ \pi r^2 = 100 \] Solving for \( r^2 \): \[ r^2 = \frac{100}{\pi} \] Taking the square root of both sides: \[ r = \sqrt{\frac{100}{\pi}} \] Step 3: The circumference of the circle is given by \( 2\pi r \). Substituting the value of \( r \): \[ \text{Circumference} = 2\pi \times \sqrt{\frac{100}{\pi}} = 20\sqrt{\pi} \, \text{cm}. \]
In the given figure, the numbers associated with the rectangle, triangle, and ellipse are 1, 2, and 3, respectively. Which one among the given options is the most appropriate combination of \( P \), \( Q \), and \( R \)?
