Question:
Aqueous CuSO4 solution was electrolysed by passing 2 amp of current for 10 min. What is the weight (in g) of copper deposited at cathode? (Cu = 63 u; F = 96500 C mol-1)
Aqueous CuSO4 solution was electrolysed by passing 2 amp of current for 10 min. What is the weight (in g) of copper deposited at cathode? (Cu = 63 u; F = 96500 C mol-1)
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The weight of copper deposited can be calculated using the formula.
Updated On: Mar 25, 2025
- 0.195
- 0.39
- 0.78
- 1.57
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The Correct Option is B
Solution and Explanation
The weight of copper deposited can be calculated using the formula:
W = (I × t × M) / (F × n)
Where:
- I = Current = 2 A
- t = Time = 10 minutes = 600 seconds
- M = Molar mass of Cu = 63 g/mol
- F = Faraday's constant = 96500 C/mol
- n = Valency of Cu = 2
Substituting the values:
W = (2 × 600 × 63) / (96500 × 2) = 0.39 g
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