Five golfers C, D, E, F and G play a series of matches in which the following are always true of the results. Either C is the last and G is the first or C is the first and G is the last. D finishes ahead of E. Every golfer plays in and finishes every match. There are no ties in any match, i.e. no two players ever finish in the same position in a match.
If exactly 1 golfer finishes between C and D, then which of the following must be true?
- C finishes first
- G finishes first
- F finishes third
- E finishes fourth
The Correct Option is D
Solution and Explanation
The correct option is (D): E finishes fourth
Given the conditions:
1. Either C is last and G is first, or C is first and G is last.
2. D finishes ahead of E.
3. There are no ties in any match.
If exactly 1 golfer finishes between C and D, let's analyze the scenarios:
- Scenario 1: If C is first, G must be last. This means C cannot have a golfer between them and D, which contradicts the condition of having 1 golfer between C and D.
- Scenario 2: If C is last, G must be first. The order would be: G, [Golfer], D, C. D finishes ahead of E, meaning E must be the golfer finishing between G and D.
So, the order can be:
- G finishes first,
- E finishes second,
- D finishes third,
- C finishes fourth.
Thus, if exactly one golfer finishes between C and D, the only statement that must be true is that **E finishes fourth**.
Therefore, the correct answer is Option D: E finishes fourth.
Which of the following CANNOT be true?
- E finishes second
- F finishes second
- F finishes ahead of F
- F finishes ahead of D
The Correct Option is A
Solution and Explanation
The correct option is (A): E finishes second
So, E finishes second can not be true.
If D finishes third, thenwhich of the following must be true?
- G finishes first
- E Finishes ahead of F
- F finishes ahead of E
- F finishes behind D
The Correct Option is C
Solution and Explanation
The correct option is (C): F finishes ahead of E
If D finishes third, we can analyze the implications based on the rules given:
1. D finishes ahead of E. This means E must be in either fourth or last position.
2. C must either be first or last, depending on G's position.
Analyzing Each Option:
- A: G finishes first.
- This could be true if C is last. However, it is not a necessity because C could finish first if G is last.
- B: E finishes ahead of F.
- This cannot be concluded directly since E could finish last, which would mean F finishes ahead of E.
- C: F finishes ahead of E.
- If D is third, E cannot be ahead of F without contradicting the rule that D finishes ahead of E. Therefore, F must finish ahead of E.
- D: F finishes behind D.
- This is not necessarily true because F could finish second while D finishes third.
Conclusion:
The only statement that must be true if D finishes third is Option C: F finishes ahead of E.
If C Finishes first, then in how many different orders is it possible for the other golfers to finish?
- 1
- 2
- 3
- 4
The Correct Option is B
Solution and Explanation
The correct option is (B): 2
If C Finishes first, then 2 different orders is it possible for the other golfers to finish
Which of the following additional conditions make it certain that F finishes second?
- C Finishes ahead of D
- D finishes ahead of F
- F finishes ahead of D
- D finishes behind G
The Correct Option is C
Solution and Explanation
The correct option is (C): F finishes ahead of D
F finishes ahead of D condition make it certain that F finishes second
Top Questions on Multi-Dimensional Arrangements
- Answer the questions based on the following information.
P drank more at the party than W and left later than V.
T drank more than P and less than V and left later than P and earlier than S.
U drank less than Q and more than V and left later than S.
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(i)A weighs twice as much as B.
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(iv) D weighs half as much as E.
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Some of the criteria of selection are as follows:
M and J go together.
O cannot be placed with N.
I cannot go with J.
N goes with H.
P and Q have to be together.
K and R go together.
Unless otherwise stated, these criteria are applicable to all the below questions:- MAT - 2006
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There are four friends A, B, C, D. One of them is a cricketer and studies Chemistry and Biology. A and play football. Both football players study Maths D is a boxer. One football player also studies physics. The boxer studies Matsha and Accounts.All the friends study two subjects each and play one game each.- MAT - 2005
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Six items U, V, W, X, Y and Z are being separated into 3 Groups - Group 1, Group 2 and Group 3, according to the following conditions.
(i) The number of items in Group 1 is less than or equal to the number of items in Group 2.
(ii) The number of items in Group 2 is less than or equal to the number of items in Group 3.
(iii) V and W cannot be in the same group.
(iv) X can be in Group 3 only if Y is in Group 3.- MAT - 2004
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