The lightest article is C because:
\(A = 9C\)
\(B = 4.5C\)
\(D = 2C\)
\(E = 4C\)
Since \(w_A > w_E > w_C\), article C is the lightest.
The correct option is (A): C
From the given conditions:
\(w_A = 9w_C\)
\(w_B = 4.5w_C\)
\(w_D = 2w_C\)
\(w_E = 4w_C\)
Since \(w_A > w_E > w_C\), article E is lighter than A and B.
The correct option is (C): A,B
From the weight relationships:
\(w_E = 4w_C\)
\(w_D = 2w_C\)
\(w_C\) is the lightest.
Since \(w_E = 4w_C\), it is clear that:
\(w_E > w_D\) (because \(4w_C > 2w_C\))
\(w_E > w_C\) (because \(4w_C > w_C\))
Thus, article E is heavier than both C and D.
From the weight relationships:
\(w_A = 9w_C\)
\(w_B = 4.5w_C\)
\(w_E = 4w_C\)
\(w_D = 2w_C\)
\(w_C\) is the base weight.
Since \(w_A = 9w_C\), article A is the heaviest in weight.
Candidate | Panel-I Time | Panel-II Time |
A | 9.30 to 9.40 | 10.10 to 10.20 |
B | 9.40 to 9.50 | 10.20 to 10.30 |
C | 9.50 to 10.00 | 10.30 to 10.40 |
D | 10.00 to 10.10 | 10.40 to 10.50 |
E | 10.10 to 10.20 | 9.30 to 9.40 |
F | 10.20 to 10.30 | 9.40 to 9.50 |
G | 10.30 to 10.40 | 9.50 to 10.00 |
H | 10.40 to 10.50 | 10.00 to 10.10 |