Comprehension
Answer the questions based on the information given below.
6 trucks (numbered 1 to 6) have to transport certain number of articles (bags + balls). If an odd numbered truck fails to transport all the articles assigned to it then it is transported by next odd numbered truck and if an even numbered truck fails to transport the required number of articles then it is transported by next even numbered truck.
The given table shows the number of articles to be transported by each of the truck, percentage/actual number of articles transported out of total number of articles to be transported, percentage/actual number of articles not transported out of total number of articles to be transported, by each of the six trucks.
Note: a) Equal number of articles has to be transported by each of the trucks.
b) The number of articles which were not transported by trucks 5 and 6, together were transported by a spare truck
The given pie-chart shows the percentage distribution of number of balls transported by each of the given trucks out of total number of balls transported by all trucks together. Sum of number of bags transported by given 6 trucks is 12360.
6 trucks (numbered 1 to 6) have to transport certain number of articles (bags + balls). If an odd numbered truck fails to transport all the articles assigned to it then it is transported by next odd numbered truck and if an even numbered truck fails to transport the required number of articles then it is transported by next even numbered truck.
The given table shows the number of articles to be transported by each of the truck, percentage/actual number of articles transported out of total number of articles to be transported, percentage/actual number of articles not transported out of total number of articles to be transported, by each of the six trucks.
Note: a) Equal number of articles has to be transported by each of the trucks.
b) The number of articles which were not transported by trucks 5 and 6, together were transported by a spare truck
| Truck | Total number of articles to be transported | Percentage/actual number of articles transported | Percentage/actual number of articles not transported |
| 1 | - | - | 1200 |
| 2 | - | 80% | - |
| 3 | - | 4500 | 25% |
| 4 | - | - | 2880 |
| 5 | - | 60% | - |
| 6 | - | 5760 | - |
Question: 1
Find the average of number bags transported by trucks 2 and 6.
Find the average of number bags transported by trucks 2 and 6.
Updated On: Aug 22, 2024
- 4800
- 3000
- 2400
- 3200
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The Correct Option is B
Solution and Explanation
Since, 1200 articles are not transported by truck 1 therefore, they must have been transported by truck 3
Also, a fixed number of articles have to be transported always.
Total articles transported by truck 3 = (\(\frac{4500}{0.75}\)) = 6000
Therefore, fixed number of articles transported by each truck = 6000 - 1200 = 4800
Therefore,
Number of articles not transported by truck 2 = 0.2 × 4800 = 960
Similarly,
Now, Sum of number of articles transported by each of the given trucks = 3600 + 3840 + 4500 + 2880 + 3780 + 5760 = 24360
Sum of number of balls transported by given 6 trucks = 24360 – 12360 = 12000
Therefore,
Required average = \(\frac{(3360 + 2640)}{2}\) = 3000
So, the correct option is (B) : 3000.
Also, a fixed number of articles have to be transported always.
Total articles transported by truck 3 = (\(\frac{4500}{0.75}\)) = 6000
Therefore, fixed number of articles transported by each truck = 6000 - 1200 = 4800
Therefore,
Number of articles not transported by truck 2 = 0.2 × 4800 = 960
Similarly,
| Truck | Total number of articles have to be transported | Number of articles transported | Number of articles not transported |
| 1 | 4800 | 4800 - 1200 = 3600 | 1200 |
| 2 | 4800 | 4800 - 960 = 3840 | 960 |
| 3 | 4800 + 1200 = 6000 | 4500 | 6000 - 4500 = 1500 |
| 4 | 4800 + 960 = 5760 | 5760 - 2880 = 2880 | 2880 |
| 5 | 4800 + 1500 = 6300 | 0.6 × 6300 = 3780 | 6300 - 3780 = 2520 |
| 6 | 4800 + 2880 = 7680 | 5760 | 7680 - 5760 = 1920 |
Sum of number of balls transported by given 6 trucks = 24360 – 12360 = 12000
Therefore,
| Truck | Total number of articles have to be transported | Number of articles transported | Number of articles not transported |
| 1 | 3600 | 0.25 × 12000 = 3000 | 3600 - 3000 = 600 |
| 2 | 3840 | 0.1 × 12000 = 1200 | 3840 - 1200 = 2640 |
| 3 | 4500 | 0.05 × 12000 = 600 | 4500 - 600 = 3900 |
| 4 | 2880 | 0.15 × 12000 = 1800 | 2880 - 1800 = 1080 |
| 5 | 3780 | 0.25 × 12000 = 3000 | 3780 - 3000 = 780 |
| 6 | 5760 | 0.2 × 12000 = 2400 | 5760 - 2400 = 3360 |
So, the correct option is (B) : 3000.
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Question: 2
Find the number of articles transported by spare trucks.
Find the number of articles transported by spare trucks.
Updated On: Aug 22, 2024
- 3240
- 4580
- 3860
- 4440
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The Correct Option is D
Solution and Explanation
Since, 1200 articles are not transported by truck 1 therefore, they must have been transported by truck 3
Also, a fixed number of articles have to be transported always.
Total articles transported by truck 3 = (\(\frac{4500}{0.75}\)) = 6000
Therefore, fixed number of articles transported by each truck = 6000 - 1200 = 4800
Therefore,
Number of articles not transported by truck 2 = 0.2 × 4800 = 960
Similarly,
Now, Sum of number of articles transported by each of the given trucks = 3600 + 3840 + 4500 + 2880 + 3780 + 5760 = 24360
Sum of number of balls transported by given 6 trucks = 24360 – 12360 = 12000
Therefore,
Required number of students = 2520 + 1920 = 4440
So, the correct option is (D) : 4440.
Also, a fixed number of articles have to be transported always.
Total articles transported by truck 3 = (\(\frac{4500}{0.75}\)) = 6000
Therefore, fixed number of articles transported by each truck = 6000 - 1200 = 4800
Therefore,
Number of articles not transported by truck 2 = 0.2 × 4800 = 960
Similarly,
| Truck | Total number of articles have to be transported | Number of articles transported | Number of articles not transported |
| 1 | 4800 | 4800 - 1200 = 3600 | 1200 |
| 2 | 4800 | 4800 - 960 = 3840 | 960 |
| 3 | 4800 + 1200 = 6000 | 4500 | 6000 - 4500 = 1500 |
| 4 | 4800 + 960 = 5760 | 5760 - 2880 = 2880 | 2880 |
| 5 | 4800 + 1500 = 6300 | 0.6 × 6300 = 3780 | 6300 - 3780 = 2520 |
| 6 | 4800 + 2880 = 7680 | 5760 | 7680 - 5760 = 1920 |
Sum of number of balls transported by given 6 trucks = 24360 – 12360 = 12000
Therefore,
| Truck | Total number of articles have to be transported | Number of articles transported | Number of articles not transported |
| 1 | 3600 | 0.25 × 12000 = 3000 | 3600 - 3000 = 600 |
| 2 | 3840 | 0.1 × 12000 = 1200 | 3840 - 1200 = 2640 |
| 3 | 4500 | 0.05 × 12000 = 600 | 4500 - 600 = 3900 |
| 4 | 2880 | 0.15 × 12000 = 1800 | 2880 - 1800 = 1080 |
| 5 | 3780 | 0.25 × 12000 = 3000 | 3780 - 3000 = 780 |
| 6 | 5760 | 0.2 × 12000 = 2400 | 5760 - 2400 = 3360 |
So, the correct option is (D) : 4440.
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Question: 3
Find the ratio of number of bags transported by truck 3 to the number of articles transported by truck 1.
Find the ratio of number of bags transported by truck 3 to the number of articles transported by truck 1.
Updated On: Aug 22, 2024
- 13 : 12
- 15 : 16
- 10 : 9
- 12 : 7
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The Correct Option is A
Solution and Explanation
Since, 1200 articles are not transported by truck 1 therefore, they must have been transported by truck 3
Also, a fixed number of articles have to be transported always.
Total articles transported by truck 3 = (\(\frac{4500}{0.75}\)) = 6000
Therefore, fixed number of articles transported by each truck = 6000 - 1200 = 4800
Therefore,
Number of articles not transported by truck 2 = 0.2 × 4800 = 960
Similarly,
Now, Sum of number of articles transported by each of the given trucks = 3600 + 3840 + 4500 + 2880 + 3780 + 5760 = 24360
Sum of number of balls transported by given 6 trucks = 24360 – 12360 = 12000
Therefore,
Required ratio = 3900 : 3600 = 13 : 12
So, the correct option is (A) : 13 : 12.
Also, a fixed number of articles have to be transported always.
Total articles transported by truck 3 = (\(\frac{4500}{0.75}\)) = 6000
Therefore, fixed number of articles transported by each truck = 6000 - 1200 = 4800
Therefore,
Number of articles not transported by truck 2 = 0.2 × 4800 = 960
Similarly,
| Truck | Total number of articles have to be transported | Number of articles transported | Number of articles not transported |
| 1 | 4800 | 4800 - 1200 = 3600 | 1200 |
| 2 | 4800 | 4800 - 960 = 3840 | 960 |
| 3 | 4800 + 1200 = 6000 | 4500 | 6000 - 4500 = 1500 |
| 4 | 4800 + 960 = 5760 | 5760 - 2880 = 2880 | 2880 |
| 5 | 4800 + 1500 = 6300 | 0.6 × 6300 = 3780 | 6300 - 3780 = 2520 |
| 6 | 4800 + 2880 = 7680 | 5760 | 7680 - 5760 = 1920 |
Sum of number of balls transported by given 6 trucks = 24360 – 12360 = 12000
Therefore,
| Truck | Total number of articles have to be transported | Number of articles transported | Number of articles not transported |
| 1 | 3600 | 0.25 × 12000 = 3000 | 3600 - 3000 = 600 |
| 2 | 3840 | 0.1 × 12000 = 1200 | 3840 - 1200 = 2640 |
| 3 | 4500 | 0.05 × 12000 = 600 | 4500 - 600 = 3900 |
| 4 | 2880 | 0.15 × 12000 = 1800 | 2880 - 1800 = 1080 |
| 5 | 3780 | 0.25 × 12000 = 3000 | 3780 - 3000 = 780 |
| 6 | 5760 | 0.2 × 12000 = 2400 | 5760 - 2400 = 3360 |
So, the correct option is (A) : 13 : 12.
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Question: 4
Number of bags transported by truck 4 is how much percent more/less than the number of articles not transported by truck 2.
Number of bags transported by truck 4 is how much percent more/less than the number of articles not transported by truck 2.
Updated On: Aug 22, 2024
- 6.5%
- 15%
- 12.5%
- 7.5%
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The Correct Option is C
Solution and Explanation
Since, 1200 articles are not transported by truck 1 therefore, they must have been transported by truck 3
Also, a fixed number of articles have to be transported always.
Total articles transported by truck 3 = (\(\frac{4500}{0.75}\)) = 6000
Therefore, fixed number of articles transported by each truck = 6000 - 1200 = 4800
Therefore,
Number of articles not transported by truck 2 = 0.2 × 4800 = 960
Similarly,
Now, Sum of number of articles transported by each of the given trucks = 3600 + 3840 + 4500 + 2880 + 3780 + 5760 = 24360
Sum of number of balls transported by given 6 trucks = 24360 – 12360 = 12000
Therefore,
Required percentage = {(1080 – 960)/960} × 100 = 12.5%
So, the correct option is (C) : 12.5%.
Also, a fixed number of articles have to be transported always.
Total articles transported by truck 3 = (\(\frac{4500}{0.75}\)) = 6000
Therefore, fixed number of articles transported by each truck = 6000 - 1200 = 4800
Therefore,
Number of articles not transported by truck 2 = 0.2 × 4800 = 960
Similarly,
| Truck | Total number of articles have to be transported | Number of articles transported | Number of articles not transported |
| 1 | 4800 | 4800 - 1200 = 3600 | 1200 |
| 2 | 4800 | 4800 - 960 = 3840 | 960 |
| 3 | 4800 + 1200 = 6000 | 4500 | 6000 - 4500 = 1500 |
| 4 | 4800 + 960 = 5760 | 5760 - 2880 = 2880 | 2880 |
| 5 | 4800 + 1500 = 6300 | 0.6 × 6300 = 3780 | 6300 - 3780 = 2520 |
| 6 | 4800 + 2880 = 7680 | 5760 | 7680 - 5760 = 1920 |
Sum of number of balls transported by given 6 trucks = 24360 – 12360 = 12000
Therefore,
| Truck | Total number of articles have to be transported | Number of articles transported | Number of articles not transported |
| 1 | 3600 | 0.25 × 12000 = 3000 | 3600 - 3000 = 600 |
| 2 | 3840 | 0.1 × 12000 = 1200 | 3840 - 1200 = 2640 |
| 3 | 4500 | 0.05 × 12000 = 600 | 4500 - 600 = 3900 |
| 4 | 2880 | 0.15 × 12000 = 1800 | 2880 - 1800 = 1080 |
| 5 | 3780 | 0.25 × 12000 = 3000 | 3780 - 3000 = 780 |
| 6 | 5760 | 0.2 × 12000 = 2400 | 5760 - 2400 = 3360 |
So, the correct option is (C) : 12.5%.
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Question: 5
Find the difference between the number of bags transported by trucks 1 and 5.
Find the difference between the number of bags transported by trucks 1 and 5.
Updated On: Aug 22, 2024
- 200
- 160
- 320
- 180
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The Correct Option is D
Solution and Explanation
Since, 1200 articles are not transported by truck 1 therefore, they must have been transported by truck 3
Also, a fixed number of articles have to be transported always.
Total articles transported by truck 3 = (\(\frac{4500}{0.75}\)) = 6000
Therefore, fixed number of articles transported by each truck = 6000 - 1200 = 4800
Therefore,
Number of articles not transported by truck 2 = 0.2 × 4800 = 960
Similarly,
Now, Sum of number of articles transported by each of the given trucks = 3600 + 3840 + 4500 + 2880 + 3780 + 5760 = 24360
Sum of number of balls transported by given 6 trucks = 24360 – 12360 = 12000
Therefore,
Required difference = 780 – 600 = 180
So, the correct option is (D) : 180.
Also, a fixed number of articles have to be transported always.
Total articles transported by truck 3 = (\(\frac{4500}{0.75}\)) = 6000
Therefore, fixed number of articles transported by each truck = 6000 - 1200 = 4800
Therefore,
Number of articles not transported by truck 2 = 0.2 × 4800 = 960
Similarly,
| Truck | Total number of articles have to be transported | Number of articles transported | Number of articles not transported |
| 1 | 4800 | 4800 - 1200 = 3600 | 1200 |
| 2 | 4800 | 4800 - 960 = 3840 | 960 |
| 3 | 4800 + 1200 = 6000 | 4500 | 6000 - 4500 = 1500 |
| 4 | 4800 + 960 = 5760 | 5760 - 2880 = 2880 | 2880 |
| 5 | 4800 + 1500 = 6300 | 0.6 × 6300 = 3780 | 6300 - 3780 = 2520 |
| 6 | 4800 + 2880 = 7680 | 5760 | 7680 - 5760 = 1920 |
Sum of number of balls transported by given 6 trucks = 24360 – 12360 = 12000
Therefore,
| Truck | Total number of articles have to be transported | Number of articles transported | Number of articles not transported |
| 1 | 3600 | 0.25 × 12000 = 3000 | 3600 - 3000 = 600 |
| 2 | 3840 | 0.1 × 12000 = 1200 | 3840 - 1200 = 2640 |
| 3 | 4500 | 0.05 × 12000 = 600 | 4500 - 600 = 3900 |
| 4 | 2880 | 0.15 × 12000 = 1800 | 2880 - 1800 = 1080 |
| 5 | 3780 | 0.25 × 12000 = 3000 | 3780 - 3000 = 780 |
| 6 | 5760 | 0.2 × 12000 = 2400 | 5760 - 2400 = 3360 |
So, the correct option is (D) : 180.
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