Step 1: Recall the bond pricing formula.
The price of a bond is given as the present value of all future coupon payments plus the present value of the face value. In other words,
\[
P = \left[ \frac{C}{(1+R)} + \frac{C}{(1+R)^2} + \ldots + \frac{C}{(1+R)^T} \right] + \frac{F}{(1+R)^T}
\]
where $P$ = Price of bond, $C$ = Annual coupon payment, $F$ = Face value, $T$ = Years to maturity, $R = 0.25$ (25 percent).
Step 2: Use given information.
- Coupon payments are in arithmetic progression: A, E, B, D, C.
- Coupon on A = 2d, on B = 4d, on C = 6d, on D = 5d, on E = 3d.
- Face value of A = 1000.
- Face value of B = 2 × Face value of E.
- Price of B = 1.75 × Price of E.
- Face value of C = Price of A.
- Price of C is greater than 1800.
- Bond A matures in 2 years.
- Bond D matures in 5 years.
- One of the bonds matures in 3 years, while two others mature in 2 years.
- Bond D has the largest face value.
Step 3: Solve for coupon size d.
Using Bond A:
Coupon payment = 2d.
Price = 1000.
Maturity = 2 years.
So,
1000 = (2d)/(1.25) + (2d)/(1.25)^2 + (1000)/(1.25)^2.
Simplify this expression step by step:
(2d/1.25) = 1.6d.
(2d)/(1.25^2) = 1.28d.
(1000)/(1.25^2) = 640.
Therefore,
1000 = 1.6d + 1.28d + 640.
1000 − 640 = 2.88d.
360 = 2.88d.
d = 125.
Thus coupon payments are:
A = 250, B = 500, C = 750, D = 625, E = 375.
Step 4: Verify Bond C’s maturity.
If Bond C matures in 2 years, its price will be less than 1800. But we know it is greater than 1800.
Therefore Bond C must mature in 3 years.
Price of C with T = 3 years:
= (750)/(1.25) + (750)/(1.25^2) + (750)/(1.25^3) + (1000)/(1.25^3).
= 600 + 480 + 384 + 512.
= 1976, which is indeed greater than 1800.
So maturity of C = 3 years.
Step 5: Apply given relation between B and E.
We know Price of B = 1.75 × Price of E.
Also, Face value of B = 2 × Face value of E.
Step 6: Use pricing formula for B.
Coupon on B = 500.
Maturity of B = 2 years.
Price of B = (500)/(1.25) + (500)/(1.25^2) + (Face value of B)/(1.25^2).
Let Face value of E = e. Then Face value of B = 2e.
So Price of B = 400 + 320 + (2e)/1.5625.
But Price of B = 1.75 × Price of E.
Step 7: Use pricing formula for E.
Coupon on E = 375.
Maturity = 2 years.
Price of E = (375)/(1.25) + (375)/(1.25^2) + (e)/(1.25^2).
= 300 + 240 + e/1.5625.
Step 8: Set up equations.
Price of B = 400 + 320 + (2e)/1.5625.
Price of E = 540 + e/1.5625.
Now, Price of B = 1.75 × Price of E.
So,
720 + (2e)/1.5625 = 1.75 × [540 + e/1.5625].
Step 9: Simplify.
Left-hand side = 720 + 1.28e.
Right-hand side = 945 + 1.12e.
So equation becomes:
720 + 1.28e = 945 + 1.12e.
Simplify:
1.28e − 1.12e = 945 − 720.
0.16e = 225.
e = 225 ÷ 0.16 = 1406.25.
Step 10: Conclude.
Therefore, the face value of Bond E is Rs. 1406.25.
\[
\boxed{1406.25 \; \text{(Option A)}}
\]