Anish made in 6 overs = 42 runs
∴ Anish made in 1 overs = \(\frac{42}{6}\)
= 7 runs
Anup made in 7 overs = 63 runs
∴ Anup made in 1 overs =\(\frac{63}{7}\)
= 9 runs
Thus, Anup made more runs per over.
For Anish:
\(\text{Runs per over (Anish)} = \frac{\text{Total runs by Anish}}{\text{Number of overs by Anish}}\)
\(\text{Runs per over (Anish)} = \frac{42 \text{ runs}}{6 \text{ overs}}\)
\(\text{Runs per over (Anish)} = 7 \text{ runs per over}\)
For Anup:
\(\text{Runs per over (Anup)} = \frac{\text{Total runs by Anup}}{\text{Number of overs by Anup}}\)
\(\text{Runs per over (Anup)} = \frac{63 \text{ runs}}{7 \text{ overs}}\)
\(\text{Runs per over (Anup)} = 9 \text{ runs per over}\)
So, the answer is Anup.
Complete the drawing shown in Fig. 9.14 to indicate where the free ends of the two wires should be joined to make the bulb glow