Preparation of aniline from nitrobenzene
(i) \(3Fe +6HCl \to 3FeCl_{2}+6H\)
(ii) \(C_{6}H_{5}NO_{2}+6H\to C_{6}H_{5}NH_{2}+2H_{2}O\)
(iii) \(FeCl_{2}+2H_{2}O\to Fe(OH)_{2}+2HCl\)
(iv) \(C_{6}H_{5}NO_{2}+2Fe(OH)_{2}+4H_{2}O\to C_{6}H_{5}NH_{2}+Fe(OH)_{3}\)
The reduction of nitrobenzene using \(Fe/HCl\) produces aniline, indicating that the nitro group is converted to an \(NH_2\) group.
So, the correct option is (B): nitrobenzene.
Statement I: Primary aliphatic amines react with HNO2 to give unstable diazonium salts.
Statement II: Primary aromatic amines react with HNO2 to form diazonium salts which are stable even above 300 K.
Choose the most appropriate answer from the options given below:
Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R
Assertion : tert-Butyl amine can be formed by Gabriel phthalimide synthesis.
Reason : It follows \(SN_1\) mechanism.
In the light of the above statements, choose the correct answer from the options given below