Let the volume of mixture A be \(200 \, \text{ml}\).
Cocoa = \(60\%\) of 200 = \(120 \, \text{ml}\)
Sugar = \(40\%\) of 200 = \(80 \, \text{ml}\)
Let the volume of mixture B be \(300 \, \text{ml}\).
Coffee = \(70\%\) of 300 = \(210 \, \text{ml}\)
Sugar = \(30\%\) of 300 = \(90 \, \text{ml}\)
Now, mixing A and B in the ratio \(2:3\):
Take 200 ml of A and 300 ml of B.
Total volume of resulting mixture \(C = 200 + 300 = 500 \, \text{ml}\)
Total sugar in C = \(80 + 90 = 170 \, \text{ml}\)
Now, mixture C is combined with an equal amount of milk:
Final volume = \(500 + 500 = 1000 \, \text{ml}\)
Sugar remains = \(170 \, \text{ml}\)
Percentage of sugar in the final mixture:
\[ \frac{170}{1000} \times 100 = 17\% \]
Correct Option: (C) 17%