Anand, Binoy, Chetan, and Dharma together have Rs 47. We can represent this mathematically as:
A + B + C + D = 47
Anand and Binoy together have Rs 27:
A + B = 27
Chetan and Anand have Rs 25:
C + A = 25
Dharma and Anand have Rs 23:
D + A = 23
We can solve these equations step-by-step:
Subtract the equation A + B = 27 from the total equation A + B + C + D = 47:
(A + B + C + D) - (A + B) = 47 - 27
C + D = 20
Now subtract A + C = 25 from C + D = 20:
(C + D) - (A + C) = 20 - 25
D - A = -5
Or we can say:
A = D + 5
Also, using D + A = 23 and substituting A = D + 5:
D + (D + 5) = 23
2D + 5 = 23
Solving for D:
2D = 18
D = 9
Substitute D = 9 back into A = D + 5:
A = 9 + 5 = 14
Now substitute A = 14 into A + B = 27 to find B:
14 + B = 27
B = 13
Therefore, the amount of money Binoy has is 13. This matches the correct answer option.