Question:

An unpolarised light of intensity I is passed through two polaroids kept one after the other with their planes parallel to each other. The intensity of light emerging from second polaroid is \(\frac{I}{4}\). The angle between the pass axes of the polaroids is

Updated On: Mar 30, 2025
  • 60°
  • 30°
  • 45°
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The Correct Option is D

Solution and Explanation

Given: 
Initial intensity of unpolarised light = \( I \)
Intensity after second polaroid = \( \frac{I}{4} \)

Step-by-Step Explanation:

Step 1: After passing through the first polaroid

The intensity of unpolarized light after passing through the first polaroid becomes exactly half:

\[ I_1 = \frac{I}{2} \]

Step 2: After passing through the second polaroid (Malus' Law)

According to Malus' law, the intensity \( I_2 \) after passing through the second polaroid is given by:

\[ I_2 = I_1 \cos^2\theta \]

where \( \theta \) is the angle between the pass axes of the two polaroids.

Substitute given values clearly:

\[ \frac{I}{4} = \frac{I}{2}\cos^2\theta \]

Simplify to clearly find the angle \( \theta \):

\[ \cos^2\theta = \frac{1}{2} \]

Thus, clearly:

\[ \cos\theta = \frac{1}{\sqrt{2}} \quad\Rightarrow\quad \theta = 45^\circ \]

Final Conclusion:
The angle between the pass axes of the polaroids is clearly 45°.

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