Given:
Initial intensity of unpolarised light = \( I \)
Intensity after second polaroid = \( \frac{I}{4} \)
Step-by-Step Explanation:
Step 1: After passing through the first polaroid
The intensity of unpolarized light after passing through the first polaroid becomes exactly half:
\[ I_1 = \frac{I}{2} \]
Step 2: After passing through the second polaroid (Malus' Law)
According to Malus' law, the intensity \( I_2 \) after passing through the second polaroid is given by:
\[ I_2 = I_1 \cos^2\theta \]
where \( \theta \) is the angle between the pass axes of the two polaroids.
Substitute given values clearly:
\[ \frac{I}{4} = \frac{I}{2}\cos^2\theta \]
Simplify to clearly find the angle \( \theta \):
\[ \cos^2\theta = \frac{1}{2} \]
Thus, clearly:
\[ \cos\theta = \frac{1}{\sqrt{2}} \quad\Rightarrow\quad \theta = 45^\circ \]
Final Conclusion:
The angle between the pass axes of the polaroids is clearly 45°.
A beam of unpolarised light of intensity \( I_0 \) is passed through a polaroid A and then through another polaroid B which is oriented so that its principal plane makes an angle of 45° relative to that of A. The intensity of emergent light is:
Two polaroide $A$ and $B$ are placed in such a way that the pass-axis of polaroids are perpendicular to each other Now, another polaroid $C$ is placed between $A$ and $B$ bisecting angle between them If intensity of unpolarized light is $I _0$ then intensity of transmitted light after passing through polaroid $B$ will be: