Question:

An undrained triaxial compression test is carried out on a saturated clay sample under a cell pressure of 50 kN/m². The sample failed at a deviator stress of 100 kN/m². The cohesion of this clay sample would be

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In an undrained triaxial test, cohesion is found using the formula \( C = \frac{{Deviator Stress}}{2} \).
Updated On: Feb 4, 2025
  • 25 kN/m²
  • 50 kN/m²
  • 75 kN/m²
  • 100 kN/m²
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The Correct Option is B

Solution and Explanation

Step 1: Using the cohesion formula. - In an undrained triaxial test, cohesion \( C \) is given by: \[ C = \frac{{Deviator Stress}}{2} \] - Given deviator stress = 100 kN/m². Step 2: Substituting values. \[ C = \frac{100}{2} = 50 { kN/m²} \] Thus, the correct answer is (B) 50 kN/m².
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