Question:
An organic compound X(molecular formula C6H7O2N) has six carbon atoms in a ring system, two double bonds and a nitro group as substituent, X is
An organic compound X(molecular formula C6H7O2N) has six carbon atoms in a ring system, two double bonds and a nitro group as substituent, X is
Updated On: May 4, 2024
- homocyclic but not aromatic
- aromatic but not homocydic
- homocyclic and aromatic
- heterocyclic and aromatic
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The Correct Option is A
Solution and Explanation
For a compound to be aromatic, it must have $(4 n+2) \pi$ electrons.
Here two double bonds are present, $4 \pi$ electrons are present in the compound. Therefore, it is anti-aromatic.
Homocyclic compounds are ring structures that consist only of carbon atoms within the ring. A nitro group is attached to the ring system as a substituent, so, $C _{6} H _{7} NO _{2}$ is homocyclic but not aromatic.
Here two double bonds are present, $4 \pi$ electrons are present in the compound. Therefore, it is anti-aromatic.
Homocyclic compounds are ring structures that consist only of carbon atoms within the ring. A nitro group is attached to the ring system as a substituent, so, $C _{6} H _{7} NO _{2}$ is homocyclic but not aromatic.
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