Question:

An organic compound (A) undergoes the following reactions:
Which of the following is compound (A)?

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Key identification reactions of naphthalene: \begin{itemize} \item Partial hydrogenation gives tetralin \item Strong oxidation gives phthalic acid \end{itemize} These reactions are frequently tested in aromatic hydrocarbon problems.
Updated On: Feb 2, 2026
  • Structure 1
  • Structure 2
  • Structure 3
  • Structure 4
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The Correct Option is A

Solution and Explanation

Given reactions:

  • Reaction 1: \( \text{H}_2, \, \text{Pt} \) (Hydrogenation)
  • Reaction 2: \( \text{Hot} \, \text{alk. KMnO}_4 \) (Oxidation to Carboxylic acid)
  • Reaction 3: \( \text{H}^+, \, \text{H}_2\text{O} \) (Acidic Hydrolysis)

The compound (A) undergoes these reactions:

\[ \text{H}_2, \, \text{Pt} \rightarrow \text{Saturated compound} \] \[ \text{Hot alk. KMnO}_4 \rightarrow \text{Carboxylation of the methyl group} \] \[ \text{H}^+, \, \text{H}_2\text{O} \rightarrow \text{Carboxylic acid formation} \]

Step-by-Step Analysis:

Let's consider the structure of compound (A). The first reaction with hydrogen (\( \text{H}_2 \)) and platinum (\( \text{Pt} \)) suggests that the compound contains a double bond or an unsaturation. Hydrogenation would reduce the unsaturation to a saturated structure. The second reaction with hot alkaline KMnO₄ is a strong oxidizing reaction that cleaves the methyl group (\( -\text{CH}_3 \)) in methylbenzene (toluene) and oxidizes it to a carboxyl group (\( -\text{COOH} \)), forming benzoic acid. The final acidic hydrolysis ensures the formation of carboxylic acid as the final product.

Conclusion: Compound (A) is likely to be toluene (methylbenzene), and after the reactions, the product will be benzoic acid.

Therefore, compound (A) corresponds to: Option 1 (Toluene), and the final product is benzoic acid.

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