An open vessel containing air is heated from 27$^\circ$C to 127$^\circ$C. The fraction of air originally present which goes out of it is
Updated On: Jul 6, 2022
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The Correct Option isB
Solution and Explanation
$\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$ initial fraction $\frac{V_{1}}{V_{2}}=1$ when temp. is $27^{\circ} C$
At $127^{*} C$, the new fraction is $\frac{V_{1}}{V_{2}}=\frac{300}{400}=\frac{3}{4}$$\therefore$ Air expelled $=1-\frac{3}{4}=\frac{1}{4}$