Question:

An object travels north with a velocity of 10ms1 10\,m{{s}^{-1}} and then speeds up to a velocity of 25ms1 25\,m{{s}^{-1}} in 5 s. The acceleration of the object in these 5 s is:

Updated On: May 20, 2022
  • 12ms2 12\,m{{s}^{-2}} in north direction
  • 3ms2 3\,m{{s}^{-2}} in north direction
  • 15ms 2 in north direction
  • 3ms2 3\,m{{s}^{-2}} in south direction
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The Correct Option is B

Solution and Explanation

Rate of change of velocity is defined as acceleration. Acceleration
a=ΔvΔt=v2v1Δt a=\frac{\Delta v}{\Delta t}=\frac{{{v}_{2}}-{{v}_{1}}}{\Delta t}
Given, v1=10m/s,v2=25ms1,Δt=5s {{v}_{1}}=10\,m/s,\,{{v}_{2}}=25\,m{{s}^{-1}},\Delta t=5s
\therefore a=25105=3ms2 a=\frac{25-10}{5}=3\,m{{s}^{-2}}
in north direction.
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Concepts Used:

Acceleration

In the real world, everything is always in motion. Objects move at a variable or a constant speed. When someone steps on the accelerator or applies brakes on a car, the speed of the car increases or decreases and the direction of the car changes. In physics, these changes in velocity or directional magnitude of a moving object are represented by acceleration

acceleration