Question:

An L-C-R circuit contains \( R = 50 \, \Omega \), \( L = 1 \, \text{mH} \), and \( C = 0.1 \, \mu\text{F} \). The impedance of the circuit will be minimum for a frequency of?

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At the resonant frequency, the impedance of an L-C-R circuit is minimized.
Updated On: Jan 12, 2026
  • \( 10^6 \, \text{Hz} \)
  • \( 2 \times 10^5 \, \text{Hz} \)
  • \( 2 \times 10^6 \, \text{Hz} \)
  • \( 10^5 \, \text{Hz} \)
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The Correct Option is B

Solution and Explanation

The impedance of an L-C-R circuit is minimized when the resonance condition is met. The resonant frequency is given by the formula: \[ f_0 = \frac{1}{2\pi \sqrt{LC}} \] Substituting the given values of \( L \) and \( C \), the resonant frequency can be calculated.
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