Question:
An ether solution of benzoic acid $ (A) $ aniline $ (B) $ and toluene $ (C) $ is extracted with aqueous $ NaOH $ . The ether layer will contain what compound $ (s) $ after the extraction ?
An ether solution of benzoic acid $ (A) $ aniline $ (B) $ and toluene $ (C) $ is extracted with aqueous $ NaOH $ . The ether layer will contain what compound $ (s) $ after the extraction ?
Updated On: Jun 14, 2022
- $ A $
- $ A + B $
- $ B + C $
- $ A+C $
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
When an ether solution of benzoic acid $(A)$ aniline $(B)$ and toluene $(C)$ is extracted with aqueous $NaOH$, then the benzoic acid $(A)$ is dissolved in aqueous $NaOH$. Therefore, the ether layer will contain aniline $(B)$ and toluene $(C)$.
Was this answer helpful?
0
0
Top Questions on Organic Chemistry- Some Basic Principles and Techniques
- The most stable carbocation among the following is:
- NEET (UG) - 2024
- Chemistry
- Organic Chemistry- Some Basic Principles and Techniques
- The compound that will undergo SN1 reaction with the fastest rate is
- NEET (UG) - 2024
- Chemistry
- Organic Chemistry- Some Basic Principles and Techniques
- Match List I with List II
List-I
(Conversion)List-II
(Shape/geometry)(A) 1 mol of H2O to O2 (I) 3F (B) 1 mol of MnO-4 to Mn2+ (II) 2F (C) 1.5 mol of Ca from molten CaCl2 (III) 1F (D) 1 mol of FeO to Fe2O3 (IV) 5F
Choose the correct answer from the options given below:- NEET (UG) - 2024
- Chemistry
- Organic Chemistry- Some Basic Principles and Techniques
- Given below are two statements :
Statement I : The boiling point of three isomeric pentanes follows the order
n-pentane > isopentane > neopentane
Statement II : When branching increases, the molecule attains a shape of sphere. This results in smaller surface area for contact, due to which the intermolecular forces between the spherical molecules are weak, thereby lowering the boiling point.
In the light of the above statements, choose the most appropriate answer from the options given below :- NEET (UG) - 2024
- Chemistry
- Organic Chemistry- Some Basic Principles and Techniques
- Match List I with List II
List-I
(Complex)List-II
(Type of isomerism)(A) [Co(NH3)5(NO2)]Cl2 (I) Solvate isomerism (B) [Co(NH3)5(SO4)]Br (II) Linkage isomerism (C) [Co(NH3)6] [Cr(CN)6] (III) Ionization isomerism (D) [Co(H2O)6]Cl3 (IV) Coordination isomerism
Choose the correct answer from the options given below:- NEET (UG) - 2024
- Chemistry
- Organic Chemistry- Some Basic Principles and Techniques
View More Questions
Questions Asked in AMUEEE exam
- The ratio of the half-life time $ (t_{1/2}) $ , to the three quarter life-time, $ (t_{3/4}) $ , for a reaction that is second order
- AMUEEE - 2018
- Order of Reaction
- $ 0.002\, M $ solution of a weak acid has an equivalent conductance $ (\wedge) 60\, ohm^{-1}\, cm^{2}\, eq^{-1} $ . What will be the $ pH $ ? (Given : $ \wedge = 400 \, ohm^{-1} \, cm^{2} \, eq^{-1} $ ]
- AMUEEE - 2018
- Electrochemistry
- The electrode potential, $ E^{\circ} $ , for the reduction of $ MnO^{-}_{4} $ to $ Mn^{2+} $ in acidic medium is $ +1.51\, V $ . Which of the following metal(s) will be oxidised? The reduction reactions and standard electrode potentials for $ Zn^{2+}, Ag^{+} $ , and $ Au^{+} $ are given as $ Zn^{2+} (aq) +2e \to Zn(s), E^{\circ} = -0.762\, V $ $ Ag+ (aq) +e {\rightleftharpoons} Ag (s), E^{\circ}=+0.80 \,V $ $ Au^{+} (aq) +e {\rightleftharpoons} Au(s), E^{\circ}+1.69\,V $
- AMUEEE - 2018
- Electrochemistry
- Three particles, two with masses $ m $ and one with mass $ M $ , might be arranged in any of the four configurations shown below. Rank the configurations according to the magnitude of the gravitational force on $ M $ , least to greatest
- AMUEEE - 2018
- Gravitation
- The $ EAN $ value $ y \left[Ti\left(\sigma-C_{6}H_{5}\right)_{2}\left(\pi-C_{5}H_{5}\right)_{2}\right]^{0} $ is
- AMUEEE - 2018
- coordination compounds
View More Questions