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an element occurring in the bcc structure has 12 0
Question:
An element occurring in the bcc structure has \( 12.08 \times 10^{23} \) unit cells. The total number of atoms of the element in these cells will be:
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In a bcc structure, each unit cell contains 2 atoms, so to find the total number of atoms, multiply by 2.
VITEEE - 2018
VITEEE
Updated On:
Jan 12, 2026
\( 24.16 \times 10^{23} \)
\( 36.18 \times 10^{23} \)
\( 6.04 \times 10^{23} \)
\( 12.08 \times 10^{23} \)
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The Correct Option is
A
Solution and Explanation
Step 1:
In the body-centered cubic (bcc) structure, there are 2 atoms per unit cell.
Step 2:
The total number of atoms in \( 12.08 \times 10^{23} \) unit cells is \( 2 \times 12.08 \times 10^{23} = 24.16 \times 10^{23} \) atoms.
Final Answer:
\[ \boxed{24.16 \times 10^{23}} \]
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