Question:

An element occurring in the bcc structure has \( 12.08 \times 10^{23} \) unit cells. The total number of atoms of the element in these cells will be:

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In a bcc structure, each unit cell contains 2 atoms, so to find the total number of atoms, multiply by 2.
Updated On: Jan 12, 2026
  • \( 24.16 \times 10^{23} \)
  • \( 36.18 \times 10^{23} \)
  • \( 6.04 \times 10^{23} \)
  • \( 12.08 \times 10^{23} \)
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The Correct Option is A

Solution and Explanation

Step 1: In the body-centered cubic (bcc) structure, there are 2 atoms per unit cell.
Step 2: The total number of atoms in \( 12.08 \times 10^{23} \) unit cells is \( 2 \times 12.08 \times 10^{23} = 24.16 \times 10^{23} \) atoms.

Final Answer: \[ \boxed{24.16 \times 10^{23}} \]
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