Step 1: Wavelength and potential difference.
The de Broglie wavelength of a particle is related to its momentum and potential difference:
\[
\lambda = \frac{h}{p}
\]
For the proton to have the same wavelength as the electron, it must be accelerated under a potential difference that gives it the same momentum.
Step 2: Calculate the required potential.
Since the mass of the proton is 2000 times that of the electron, the required potential difference is 2000 V for the proton.
Final Answer:
\[
\boxed{2000 \, \text{V}}
\]