An electric dipole with dipole moment \(4 × 10^{−9} Cm\) is aligned at \(30^0\) with the direction of a uniform electric field of magnitude \(5 × 10^4 N C^{−1}\) Calculate the magnitude of the torque acting on the dipole.
Electric dipole moment, \(p = 4 × 10^{−9}Cm\)
Angle made by p with a uniform electric field, \(\theta= 30^0\)
Electric field, \(E = 5 × 10 ^4 N C^{−1}\)
Torque acting on the dipole is given by the relation, \(\tau= pE sin\theta\)
\(= 4 × 10^{-9} × 5 × 10^4 × sin 30 = 20 × 10^{-5}×\frac{1}{2} = 10^{ -4 }Nm.\)
Therefore, the magnitude of the torque acting on the dipole is \(10^{−4} N m.\)
A dipole of moment \(\overrightarrow{p}\) is placed in uniform electric field \(\overrightarrow{E}\) then torque acting on it is given by : -
Four point charges \(q_A\)\( = 2 µC\), \(q_B\) \(= −5 µC\), \(q_C\) = 2 µC, and \(q_D\) \(= −5 µC\) are located at the corners of a square ABCD of side 10 cm. What is the force on a charge of 1 µC placed at the centre of the square?