A torque = pE acts on an electric dipole when it is positioned in an electric field E.
The dipole is being rotated via an angle by this torque.
Work done by an external force is provided by if the dipole is rotated from angle 1 to 2.
W=pE (cos 1+cos 2)
(i) When we enter 1= 0° and 2 = 90° in Eq. (i), we obtain W=pE (cos0°cos90°)= pE(10) =pE.
Therefore, the correct option is (D): pE
A dipole of moment \(\overrightarrow{p}\) is placed in uniform electric field \(\overrightarrow{E}\) then torque acting on it is given by : -
Four point charges \(q_A\)\( = 2 µC\), \(q_B\) \(= −5 µC\), \(q_C\) = 2 µC, and \(q_D\) \(= −5 µC\) are located at the corners of a square ABCD of side 10 cm. What is the force on a charge of 1 µC placed at the centre of the square?
Two large, thin metal plates are parallel and close to each other. On their inner faces, the plates have surface charge densities of opposite signs and of magnitude \(17.0 × 10^{−22} Cm^{-2}\). What is E:
(a) in the outer region of the first plate,
(b) in the outer region of the second plate, and (c) between the plates?
Electric Field is the electric force experienced by a unit charge.
The electric force is calculated using the coulomb's law, whose formula is:
\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)
While substituting q2 as 1, electric field becomes:
\(E=k\dfrac{|q_{1}|}{r^{2}}\)
SI unit of Electric Field is V/m (Volt per meter).