Question:

An electric dipole is placed along the x-axis at the origin 0. A point P is at a distance of 20 cm from this origin such that OP makes an angle $ \text{/3} $ with the x-axis. If the electric field at P makes an angle $ \theta $ with the x-axis, the value of $ \theta $ would be

Updated On: Jul 27, 2022
  • $ \frac{\pi }{3} $
  • $ \frac{\pi }{3}+{{\tan }^{-1}}\left( \frac{\sqrt{3}}{2} \right) $
  • $ \frac{2\pi }{3} $
  • $ {{\tan }^{-1}}\left( \frac{\sqrt{3}}{2} \right) $
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The Correct Option is B

Solution and Explanation

Component of electric field at point P parallel to $ X- $ axis, $ {{E}_{X}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{2(p\cos \pi /3)}{{{r}^{3}}} $ $ \frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{P}{{{r}^{3}}} $ Component of electric field of point $ P $ perpendicular to $ X- $ axis, $ {{E}_{Y}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{p\sin \pi /3}{{{r}^{3}}} $ $ =\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{\sqrt{3}p}{2{{r}^{3}}} $ $ \therefore $ $ \tan \theta =\frac{{{E}_{Y}}}{{{E}_{X}}}=\frac{\sqrt{3}}{2} $ $ \therefore $ $ \theta ={{\tan }^{-1}}\left( \frac{\sqrt{3}}{2} \right) $
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Concepts Used:

Electric Dipole

An electric dipole is a pair of equal and opposite point charges -q and q, separated by a distance of 2a. The direction from q to -q is said to be the direction in space.

p=q×2a

where,

p denotes the electric dipole moment, pointing from the negative charge to the positive charge.

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