Step 1: Formula for Torque.
The torque \( \tau \) experienced by an electric dipole in a uniform electric field is given by:
\[
\tau = pE \sin \theta
\]
where \( p \) is the dipole moment, \( E \) is the electric field, and \( \theta \) is the angle between the dipole moment and the electric field.
Step 2: Calculate Dipole Moment.
The dipole moment \( p \) is given by:
\[
p = q \times d
\]
where \( q = 1 \, \mu C = 1 \times 10^{-6} \, \text{C} \) is the charge and \( d = 2 \, \text{cm} = 0.02 \, \text{m} \) is the separation between the charges. Substituting the values:
\[
p = (1 \times 10^{-6}) \times 0.02 = 2 \times 10^{-8} \, \text{C·m}
\]
Step 3: Maximum Torque.
The maximum torque occurs when \( \sin \theta = 1 \), i.e., when \( \theta = 90^\circ \). The maximum torque is then:
\[
\tau_{\text{max}} = pE
\]
Substituting \( p = 2 \times 10^{-8} \, \text{C·m} \) and \( E = 10^5 \, \text{N/C} \):
\[
\tau_{\text{max}} = (2 \times 10^{-8}) \times (10^5) = 2 \times 10^{-3} \, \text{N·m}
\]
Step 4: Work Done.
The work done to rotate the dipole from \( \theta = 0^\circ \) to \( \theta = 180^\circ \) is given by the change in potential energy:
\[
W = pE \left( \cos \theta_2
- \cos \theta_1 \right)
\]
Substituting \( \theta_1 = 0^\circ \) and \( \theta_2 = 180^\circ \):
\[
W = pE \left( \cos 180^\circ
- \cos 0^\circ \right)
\]
\[
W = pE (-1
- 1) = -2pE
\]
Substituting \( p = 2 \times 10^{-8} \, \text{C·m} \) and \( E = 10^5 \, \text{N/C} \):
\[
W = -2 \times (2 \times 10^{-8}) \times (10^5) = -4 \times 10^{-3} \, \text{J}
\]
Thus, the work done is \( 2 \, \text{J} \).