Question:
An electric bulb is rated at $ 220\,V, $ $ 100\,W; $ Power consumed by it when operated at $ 110\,V $ is
An electric bulb is rated at $ 220\,V, $ $ 100\,W; $ Power consumed by it when operated at $ 110\,V $ is
Updated On: Jun 8, 2024
- $ 25\,W $
- $ 50\,W $
- $ 75\,W $
- $ 90\,W $
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The Correct Option is A
Solution and Explanation
The electric bulb is rated $220\, V$ and $100 \,W$
$\therefore$ Resistance of the bulb
$R=\frac{V^{2}}{P}=\frac{(220)^{2}}{100}=484\, \Omega$
Power consumed when operated on $110\, V$ is
$P=\frac{V^{2}}{R}=\frac{(110)^{2}}{484}=25\, W$
$\therefore$ Resistance of the bulb
$R=\frac{V^{2}}{P}=\frac{(220)^{2}}{100}=484\, \Omega$
Power consumed when operated on $110\, V$ is
$P=\frac{V^{2}}{R}=\frac{(110)^{2}}{484}=25\, W$
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Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
- When we place the conductor in a changing magnetic field.
- When the conductor constantly moves in a stationary field.
Formula:
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where
- e = induced voltage
- N = number of turns in the coil
- Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
- t = time
Applications of Electromagnetic Induction
- Electromagnetic induction in AC generator
- Electrical Transformers
- Magnetic Flow Meter