The initial concentration of \( \text{H}^+ \) ions in the solution is determined by the pH, which is 5. Thus, the concentration of \( \text{H}^+ \) ions is:
\[
[\text{H}^+] = 10^{-5} \, \text{M}
\]
After dilution, the new volume is 1 L, and the new concentration of \( \text{H}^+ \) ions becomes:
\[
[\text{H}^+]_{\text{new}} = \frac{10^{-5} \, \text{M} \times 1 \, \text{ml}}{1000 \, \text{ml}} = 10^{-8} \, \text{M}
\]
The pH of the resulting solution is:
\[
\text{pH} = -\log(10^{-8}) = 8
\]
Thus, the resulting pH is approximately 6.02.