Question

An analog transducer has a resolution of 0.01%. Calculate the number of bits required for A/D conversion.

• A. 10
• B. 6
• C. 14
• D. 12

Hint:

Use \( \text{Resolution} = \frac{1}{2^n} \times 100\% \) to find number of bits \( n \).

Answer 1

The Correct Option is C

Resolution = \( \frac{1}{2^n} \times 100% \) Given: \( \frac{1}{2^n} \times 100 = 0.01 \Rightarrow 2^n = 10,000 \) Taking log: \[ n = \log_2(10000) \approx \frac{\log_{10}(10000)}{\log_{10}(2)} = \frac{4}{0.3010} \approx 13.29 \Rightarrow n = 14 \]