As per the given information, 'A' on ozonolysis gives two moles of an aldehyde of molar mass 44 u. The formation of two moles of an aldehyde indicates the presence of identical structural units on both sides of the double bond containing carbon atoms. Hence, the structure of 'A' can be represented as:
XC = CX
There are eight C-H σ bonds. Hence, there are 8 hydrogen atoms in 'A'. Also, there are three C-C bonds. Hence, there are four carbon atoms present in the structure of 'A'.
Combining the inferences, the structure of 'A' can be represented as:
'A' has 3 C-C bonds, 8 C-H σ bonds, and one C-C \(\pi\) bond.
Hence, the IUPAC name of 'A' is But-2-ene.
Ozonolysis of 'A' takes place as:
The final product is ethanal with molecular mass
= [(2x12)+(4x1)+(1x16)]
= 44 u.
The molality of a 10% (v/v) solution of di-bromine solution in \(\text{CCl}_4\) (carbon tetrachloride) is \(x\). \(x = \, \_\_\_\_\ \times 10^{-2} \, \text{M}\). (Nearest integer)
Given:
Molar mass of \(\text{Br}_2 = 160 \, \text{g mol}^{-1}\)
Atomic mass of \(\text{C} = 12 \, \text{g mol}^{-1}\)
Atomic mass of \(\text{Cl} = 35.5 \, \text{g mol}^{-1}\)
Density of dibromine = \(3.2 \, \text{g cm}^{-3}\)
Density of \(\text{CCl}_4 = 1.6 \, \text{g cm}^{-3}\)
An alkene X on ozonolysis gives a mixture of Propan-2-one and methanal. What is X?
In organic chemistry, an alkene is a hydrocarbon containing a carbon-carbon double bond.[1]
Alkene is often used as synonym of olefin, that is, any hydrocarbon containing one or more double bonds.
Read More: Ozonolysis
Read More: Unsaturated Hydrocarbon