Question:

An alcohol \( X \) (\( C_4H_{10}O \)) does not give turbidity with conc. HCl and ZnCl\(_2\) at room temperature. \( X \) on reaction with reagent \( Y \) gives \( Z \). What are \( X \), \( Y \), and \( Z \) respectively?

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Lucas test distinguishes alcohols:
- Primary alcohols show no reaction at room temperature.
- Secondary alcohols react slowly.
- Tertiary alcohols react immediately.
Updated On: Mar 24, 2025
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The Correct Option is A

Solution and Explanation

Step 1: Identify \( X \) - The given molecular formula \( C_4H_{10}O \) suggests a butanol isomer.
- Since \( X \) does not give turbidity with Lucas reagent (conc. HCl + ZnCl\(_2\)), it must be a primary alcohol.
- The correct structure for \( X \) is 1-Butanol (\chemfig{CCCOH}). Step 2: Identify \( Y \) - PCC (Pyridinium chlorochromate) is a mild oxidizing agent.
- It selectively oxidizes primary alcohols to aldehydes without further oxidation to carboxylic acids.
- Therefore, \( Y \) is PCC. Step 3: Identify \( Z \) - The oxidation of 1-Butanol (\chemfig{CCCOH}) using PCC yields butanal (\chemfig{CCC=O}), an aldehyde.
- Thus, \( Z \) is Butanal.
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