Question:

An aeroplane when 3000 m high passes vertically above another aeroplane at an instant when the angles of elevation of the two aeroplanes from the same point on the ground are \(60\degree\) and \(45\degree\) respectively. The vertical distance between the two aeroplanes is

Updated On: Oct 10, 2024
  • 1268 m
  • 1500m
  • 3000m
  • 1200m
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The Correct Option is A

Solution and Explanation

Angle of elevation
In \(\triangle\)ABC
tan 60°=\(\frac{3000}{BC}\)
BC = \(\frac{3000}{\sqrt{3}}\)m ………..(i)
In \(\triangle\)BCD
tan 45°=\(\frac{3000 - h}{BC}\)
BC = 3000 − h   ……. (ii)
Equating and solving equations (i) and (ii), we get
h = 1268m
So the correct option is (A).
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