Question:

An aeroplane flying horizontally with a speed of 720 kmph at an altitude of 490 m drops a bomb when it is just vertically above a target. The horizontal distance between the target and the point where the bomb strikes the ground is

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Convert all units to SI and use projectile motion formulae to solve horizontal bomb drop problems.
Updated On: Jun 3, 2025
  • 1106 m
  • 1200 m
  • 2000 m
  • 800 m
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The Correct Option is C

Solution and Explanation

Speed = 720 kmph = \( \dfrac{720 \times 1000}{60 \times 60} = 200\ \mathrm{m/s} \)
Height = 490 m
Time to fall = \( \sqrt{\dfrac{2h}{g}} = \sqrt{\dfrac{2 \times 490}{9.8}} = \sqrt{100} = 10\ \mathrm{s} \)
Horizontal distance = speed × time = 200 × 10 = 2000 m
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