Question:

An a.c. generator consists of a coil of $100$ turns and cross-sectional area of $3 \,m^{2}$, rotating at a constant angular speed of $60$ radian/sec in a uniform magnetic field of $0.04 \,T$. The resistance of the coil is $500$ ohm. What is the maximum power dissipation in the coil?

Updated On: Jul 6, 2022
  • $518.4\,W$
  • $1036\,W$
  • $259.2\,W$
  • Zero
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The Correct Option is A

Solution and Explanation

Here, $N=100, A=3\,m^{2}, \omega=60\,rad \,s^{-1}, B=0.04\,T$, $R=500\,\Omega$ Max. power dissipation $=\varepsilon_{eff\cdot I_{eff}} =\frac{\varepsilon_{0}}{\sqrt{2}}\cdot\frac{I_{0}}{\sqrt{2}}=\frac{I_{0}^{2}R}{2}$ $=\frac{\left(1.44\right)^{2}\times500}{2}$ $=518.4\,W$
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Top Questions on Electromagnetic induction

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Concepts Used:

Electromagnetic Induction

Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-

  1. When we place the conductor in a changing magnetic field.
  2. When the conductor constantly moves in a stationary field.

Formula:

The electromagnetic induction is mathematically represented as:-

e=N × d∅.dt

Where

  • e = induced voltage
  • N = number of turns in the coil
  • Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
  • t = time

Applications of Electromagnetic Induction

  1. Electromagnetic induction in AC generator
  2. Electrical Transformers
  3. Magnetic Flow Meter