2
4
1
3
Let's analyze each species:
NH3 (Ammonia): Nitrogen (N) has 5 valence electrons. In NH3, there are three shared electron pairs around nitrogen (one from each hydrogen atom). The total number of electrons around the central nitrogen atom is 3 x 2 (shared pairs) + 2 (non-bonding pair) = 8. So, NH3 has eight electrons around the central atom.
AlCl3 (Aluminum trichloride): Aluminum (Al) has 3 valence electrons, and chlorine (Cl) has 7 valence electrons each. In AlCl3, aluminum forms three bonds with chlorine, and each chlorine atom has 3 lone pairs. The total number of electrons around the central aluminum atom is 3 x 2 (shared pairs) + 6 (non-bonding pairs) = 12. So, AlCl3 does not have eight electrons around the central atom.
BeCl2 (Beryllium dichloride): Beryllium (Be) has 2 valence electrons, and chlorine (Cl) has 7 valence electrons each. In BeCl2, beryllium forms two bonds with chlorine, and each chlorine atom has 3 lone pairs. The total number of electrons around the central beryllium atom is 2 x 2 (shared pairs) + 6 (non-bonding pairs) = 10. So, BeCl2 does not have eight electrons around the central atom.
CCl4 (Carbon tetrachloride): Carbon (C) has 4 valence electrons, and chlorine (Cl) has 7 valence electrons each. In CCl4, carbon forms four bonds with chlorine. The total number of electrons around the central carbon atom is 4 x 2 (shared pairs) = 8. So, CCl4 has eight electrons around the central atom.
PCl5 (Phosphorus pentachloride): Phosphorus (P) has 5 valence electrons, and chlorine (Cl) has 7 valence electrons each. In PCl5, phosphorus forms five bonds with chlorine. The total number of electrons around the central phosphorus atom is 5 x 2 (shared pairs) = 10. So, PCl5 does not have eight electrons around the central atom.
Now, let's count the species that do not have eight electrons around the central atom:
AlCl3, BeCl2, PCl5 (3 species)
The correct answer is (D): 3.
Identify the correct orders against the property mentioned:
A. H$_2$O $>$ NH$_3$ $>$ CHCl$_3$ - dipole moment
B. XeF$_4$ $>$ XeO$_3$ $>$ XeF$_2$ - number of lone pairs on central atom
C. O–H $>$ C–H $>$ N–O - bond length
D. N$_2$>O$_2$>H$_2$ - bond enthalpy
Choose the correct answer from the options given below:
A sphere of radius R is cut from a larger solid sphere of radius 2R as shown in the figure. The ratio of the moment of inertia of the smaller sphere to that of the rest part of the sphere about the Y-axis is : 
A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is :
The current passing through the battery in the given circuit, is: 
Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.
There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds.