Question:

Among the following the third ionization energy is highest for

Updated On: Jun 14, 2022
  • magnesium
  • boron
  • beryllium
  • aluminium
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The Correct Option is C

Solution and Explanation

The electronic configuration of the given elements is as
${ }_{12} Mg =[ Ne ] 3 s^{2}$
${ }_{5} B =[ He ] 2 s^{2}, 2 p^{1}$
${ }_{4} Be =[ He ] 2 s^{2}$
${ }_{13} Al =[ Ne ] 3 s^{2} 3 p^{1}$
From the electronic configuration, it is clear that third ionisation energy of $Mg$ and $Be$ is higher as compared to $Al$ and $B$ as in them the third electron have to be removed from the stable inert gas configuration.
Between Mg and Be, third $IE$ of $Be$ is higher because of its smaller size.
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Concepts Used:

Haloalkanes and Haloarenes - Classification

Classification of Haloalkanes and Haloarenes are as follows:

Haloalkanes and Haloarenes are Classified on the Basis of the Number of Halogen Atoms:

These are further classified as mono, di, or polyhalogen (tri-,tetra-, etc.) compounds depending on whether they contain one, two or more halogen atoms in their structures. For example;

  • Monohaloalkane
  • Dihaloalkane
  • Trihaloalkane

Haloalkanes and Haloarenes are Classified on Compounds Containing sp3 C—X Bond (X= F, Cl, Br, I)

This class includes:

  • Alkyl halides or haloalkanes (R—X)
  • Allylic halides
  • Benzylic halides

Haloalkanes and Haloarenes are Classified on Compounds Containing sp2 C—X Bond

This class includes:

  • Vinylic halides
  • Aryl halides