Step 1: Understanding the bond angle.
In molecules with a trigonal pyramidal shape like \( \text{NH}_3 \), \( \text{PH}_3 \), and \( \text{NF}_3 \), the bond angle is determined by the electron pair repulsion, which is the highest in the case of \( \text{NH}_3 \) (around 107°), and the lowest in the case of \( \text{PH}_3 \) (around 93.5°). This occurs due to the lower electronegativity of phosphorus compared to nitrogen, resulting in weaker repulsion between the bonding electrons in \( \text{PH}_3 \).
Step 2: Analyzing the options.
- (A) \( \text{PH}_3 \): The bond angle in \( \text{PH}_3 \) is the smallest due to weaker bonding electron repulsion.
- (B) \( \text{PF}_3 \): The bond angle in \( \text{PF}_3 \) is smaller than in \( \text{NH}_3 \) but larger than in \( \text{PH}_3 \).
- (C) \( \text{NF}_3 \): The bond angle is slightly smaller than \( \text{NH}_3 \), but larger than \( \text{PH}_3 \).
- (D) \( \text{NH}_3 \): The bond angle in \( \text{NH}_3 \) is larger than in \( \text{PH}_3 \), but smaller than in ideal trigonal pyramidal geometry (107°).
Step 3: Conclusion.
The correct answer is (A) \( \text{PH}_3 \), as it has the smallest bond angle among the given molecules.