Let's denote the rates of work of Amar, Akbar, and Anthony as A, B, and C units/year, respectively.
From the given data:
1. Amar and Akbar together can complete the project in 1 year. \(A + B = 1\) (1)
2. Akbar and Anthony together can complete the project in 16 months (or 4/3 years). \(B + C = 3/4\) (2)
3. Anthony and Amar together can complete the project in 2 years. \(C + A = 1/2\) (3)
Adding all three equations, we get: 2(A + B + C) = 1 + 3/4 + 1/2 2(A + B + C) = 9/4 A + B + C = 9/8
From equation (1), we get: A = 1 - B
Plugging this into \(A + B + C = 9/8\):
1 - B + B + C = 9/8
1 + C = 9/8
C = 1/8
From equation (2):
B = 3/4 - 1/8 = 5/8
Now, let's identify the worker who is neither the fastest nor the slowest:
A = 1 - 5/8 = 3/8
B = 5/8
C = 1/8
Clearly, Akbar (B) is neither the fastest nor the slowest
If he works alone, he will take:
Time = Total work/Rate = 1 / (5/8) = 8/5 years = 19.2 months.
So, Akbar will take approximately 19.2 months to complete the project on his own