Aluminum reacts with dilute HCL and liberates a gas 'A' and with aqueous alkali liberates a gas 'B'. A and B respectively are
Cl2, O2
O2,O2
Cl2.H2
H2,H2
To solve the problem, we need to identify the gases evolved when aluminium reacts with dilute hydrochloric acid and with aqueous alkali.
1. Reaction with Dilute HCl:
Aluminium is a reactive metal and reacts with dilute hydrochloric acid to liberate hydrogen gas ($H_2$):
$2Al + 6HCl \rightarrow 2AlCl_3 + 3H_2 \uparrow$
So, gas ‘A’ is Hydrogen ($H_2$).
2. Reaction with Aqueous Alkali:
Aluminium is amphoteric — it reacts with bases like NaOH to form sodium aluminate and hydrogen gas:
$2Al + 2NaOH + 6H_2O \rightarrow 2Na[Al(OH)_4] + 3H_2 \uparrow$
So, gas ‘B’ is also Hydrogen ($H_2$).
Final Answer:
The gases A and B liberated in the two reactions are H2, H2.
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