- Given that the vertices of the right-angled triangle lie on the circumference of a circle, the hypotenuse of the triangle is the diameter of the circle.
- The sides of the right-angled triangle are 14 cm and 48 cm.
- Using the Pythagorean theorem to find the hypotenuse:
\[ h = \sqrt{14^2 + 48^2} = \sqrt{196 + 2304} = \sqrt{2500} = 50 \text{ cm} \]
- Thus, the diameter of the circle is 50 cm.
- The radius \(r\) of the circle is half of the diameter:
\[ r = \frac{50}{2} = 25 \text{ cm} \]
- The area \(A\) of the circle is given by the formula:
\[ A = \pi r^2 = \pi \times 25^2 = \pi \times 625 = 625\pi \text{ cm²} \]
Thus, the area of the circle is 625π cm².
Conclusion: The correct answer is 625π cm².
On the day of her examination, Riya sharpened her pencil from both ends as shown below. 
The diameter of the cylindrical and conical part of the pencil is 4.2 mm. If the height of each conical part is 2.8 mm and the length of the entire pencil is 105.6 mm, find the total surface area of the pencil.
Two identical cones are joined as shown in the figure. If radius of base is 4 cm and slant height of the cone is 6 cm, then height of the solid is
From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.
Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$