Question:

Alkali metals are not found in free state due to their highly reactive nature. This is due to

Updated On: Jul 6, 2022
  • their large size and low ionisation enthalpy
  • their large size and high ionisation enthalpy
  • their low ionisation enthalpy and high electron gain enthalpy
  • their tendency to impart colour to the flame
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Solution and Explanation

Their reactivity depends on how easily the element can lose their electron to achieve the nearest noble gas configuration. All the alkali metals have one valence electron $ns ^{1}$. outside the noble gas core. The loosely held s-electron in the outermost valence shell of these elements makes them the most electropositive metals. They readily lose electron to give monovalent $M ^{+}$ions. As the atomic size increases, the no. of shells increases so the force of attraction between the nucleus and the electron of the valence shell decreases, so they can easily lose electron upon irradiation to heat and light, so they have low ionization enthalpy. Therefore, alkali metals are not found in the free state, they are commonly found as metal oxides, metal carbonates etc.
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Concepts Used:

Group 1 Elements

Group one of alkali metals is s-block elements with just one electron in their s-orbital. They are are alkali metals. They are named so because of the alkaline nature of the hydroxides and oxides.

Alkali metals are characterized by one s-electron in the valence shell of their atoms.

Alkali metals have a corresponding [Noble gas] ns1 electronic configuration. They occupy the first column of the periodic table. Alkali elements are:

  • Lithium(Li)
  • Sodium(Na)
  • Potassium (K)
  • Rubidium (Ru)
  • Cesium (Cs)
  • Francium (Fr)

They have occupied successive periods from first to seven. Francium is a radioactive element with very low half-life.

Electronic Configuration:

  • Alkali metals have one electron in their valence shell.
  • The electronic configuration is given by ns1. For example, the electronic configuration of lithium is given by 1ns1 2ns1.
  • They tend to lose the outer shell electron to form cations with charge +1 (monovalent ions).

This makes them the most electropositive elements and due to the same reason, they are not found in the pure state.