Question:

Aldose: What type of monosaccharides are fructose, glucose, and xylose? To which family do they belong based on their functional groups?

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Monosaccharides are classified into aldoses or ketoses based on the presence of an aldehyde group (\( -CHO \)) or a keto group (\( -C=O \)). This distinction helps identify their structure and behavior in biochemical processes.
Updated On: Jan 17, 2025
  • \( \text{Fructose is a ketose, glucose and xylose are aldoses.} \)
  • \( \text{Fructose and glucose are ketoses, xylose is an aldose.} \)
  • \( \text{All three are aldoses.} \)
  • \( \text{All three are ketoses.} \)
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The Correct Option is A

Solution and Explanation

Monosaccharides are simple sugars classified based on their functional groups. The two main classifications are aldoses and ketoses, which are determined by the presence of either an aldehyde or a keto group. Step 1: Identifying Aldoses and Ketoses.
Aldoses are sugars that contain an aldehyde group (\( -CHO \)), which is typically located at the first carbon atom in the molecule. Ketoses are sugars that contain a keto group (\( -C=O \)), which is usually located at the second carbon atom in the molecule. Step 2: Functional Groups of Fructose, Glucose, and Xylose.
Let’s analyze the functional groups of each monosaccharide: Fructose is a ketose because it contains a keto group at the second carbon atom, making it a ketohexose (6-carbon ketose). Glucose is an aldose because it contains an aldehyde group at the first carbon atom, making it an aldohexose (6-carbon aldose). Xylose is also an aldose because it contains an aldehyde group at the first carbon atom, making it an aldopentose (5-carbon aldose). Step 3: Family Classification.
Glucose: This monosaccharide belongs to the aldohexose family due to its 6 carbon atoms and aldehyde group. Xylose: This monosaccharide belongs to the aldopentose family due to its 5 carbon atoms and aldehyde group. Fructose: This monosaccharide belongs to the ketohexose family due to its 6 carbon atoms and keto group. Thus, the correct conclusion is: \[ \text{Fructose is a ketose, glucose and xylose are aldoses.} \] Therefore, the correct answer is \( \mathbf{(1)} \).
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