Question:

Addition theorem of probability is.

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In the case of mutually exclusive events, the probability of their union is simply \( P(A \cup B) = P(A) + P(B) \), as \( P(A \cap B) = 0 \).
  • \( P(A \cup B) = P(A) + P(B) \)
  • \( P(A \cup B) = P(A) + P(B) - P(A \cap B) \)
  • \( P(A \cup B) = P(A) + P(B) - P(A \cup B) \)
  • \( P(A \cup B) = P(A) \cdot P(B) \)
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The Correct Option is B

Solution and Explanation

The addition theorem of probability states that the probability of the union of two events \( A \) and \( B \) is given by: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B). \] This formula accounts for the fact that the overlap (intersection) of \( A \) and \( B \) is counted twice when we simply add \( P(A) \) and \( P(B) \), so we subtract \( P(A \cap B) \) to correct for that.
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