According to the valence bond theory, the metal atom or ion under the influence of ligands can use its (n-1)d, ns, n, nd orbitals for hybridisation to yield a set of equivalent orbitals of definite geometry. These hybridised orbitals are allowed to overlap with ligand orbitals that can donate electron pairs for bonding. It is usually possible to predict the geometry of a complex from the knowledge of its magnetic behaviour on the basis of the valence bond theory. Consider the formation of [Co (NH3)5Cl] Cl2, and answer the following question
The IUPAC name of the above coordination entity is
The IUPAC name of the above coordination entity is
Chloridopentaamminecobaltate (II) chloride
Chloridopentaamminecobaltate (II) dichloride
Pentaamminechloridocobaltate (III) chloride
Pentaamminechloridocobalt (III) dichloride
The Correct Option is C
Solution and Explanation
The IUPAC name of the coordination entity [Co(NH3)5Cl]Cl2 is "Pentaamminechloridocobaltate (III) chloride".
The spin only magnetic moment of the complex [Co (NH3)5Cl] Cl2 in BM is
The spin only magnetic moment of the complex [Co (NH3)5Cl] Cl2 in BM is
1.7
0
3.8
4.9
The Correct Option is C
Solution and Explanation
To determine the spin-only magnetic moment of the complex [Co(NH3)5Cl]Cl2, we need to know the number of unpaired electrons in the d-orbital of the central cobalt ion.
In this complex, cobalt is in the +3 oxidation state, which means it has lost three electrons. Cobalt has the electron configuration [Ar] 3d7, so it has three unpaired electrons. The spin-only magnetic moment (μ) can be calculated using the formula: μ = √(n(n+2)) BM
where n is the number of unpaired electrons.
Substituting n = 3 into the formula, we get: μ = √(3(3+2)) = √15 ≈ 3.87 BM
Therefore, the spin-only magnetic moment of the complex [Co(NH3)5Cl]Cl2 is approximately 3.87 BM.
The hybridization of cobalt in the above coordination entity is
The hybridization of cobalt in the above coordination entity is
sp3d2
d2sp3
sp3d
dsp3
The Correct Option is A
Solution and Explanation
In the complex [Co(NH3)5Cl]Cl2, the central cobalt atom undergoes hybridization to form its bonding orbitals. The coordination number of cobalt in this complex is 6, suggesting that it forms six bonds with its surrounding ligands.
To determine the hybridization of cobalt, we can consider its electronic configuration. Cobalt has the atomic number 27, and its ground-state electron configuration is [Ar] 3d7 4s2.
In this complex, cobalt is in the +3 oxidation state, which means it has lost three electrons. Therefore, the electron configuration of cobalt in the complex is [Ar] 3d7.
|To accommodate the six bonding regions around cobalt, it undergoes sp3d2 hybridization, which involves the mixing of one 4s orbital, three 4p orbitals, and two 4d orbitals to form six equivalent hybrid orbitals.
These six hybrid orbitals are then used to form bonds with the ligands in the complex. So, the hybridization of cobalt in the complex [Co(NH3)5Cl]Cl2 is sp3d2.
The coordination number of cobalt in the above coordination entity is
The coordination number of cobalt in the above coordination entity is
2
4
5
6
The Correct Option is D
Solution and Explanation
The coordination number of cobalt in the complex [Co(NH3)5Cl]Cl2 is 6.
The primary valence of Co in above coordination entity is
The primary valence of Co in above coordination entity is
1
2
3
4
The Correct Option is C
Solution and Explanation
The primary valence of Co in the coordination entity [Co(NH3)5Cl]Cl2 is 3
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