Question:

According to Bohr’s theory, the angular momentum for an electron of third orbit is?

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Bohr's theory quantizes the angular momentum of electrons as \( L = \frac{nh}{2\pi} \).
Updated On: Jan 12, 2026
  • \( \frac{h}{2\pi} \)
  • \( \frac{3h}{2\pi} \)
  • \( \frac{h}{\pi} \)
  • \( \frac{2h}{\pi} \)
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The Correct Option is B

Solution and Explanation

According to Bohr’s theory, the angular momentum of an electron in the nth orbit is quantized and given by: \[ L = \frac{nh}{2\pi} \] For the third orbit, \( n = 3 \), so the angular momentum is \( \frac{3h}{2\pi} \).
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