Question:

According to Bernoullis equation $ \frac{P}{\rho g}+h+\frac{1}{2}\frac{{{v}^{2}}}{g}=\text{constant} $ The terms A, B and C are generally called respectively:

Updated On: Aug 5, 2023
  • gravitational head, pressure head and velocity head
  • gravity, gravitational head and velocity head
  • pressure head, gravitational head and velocity head
  • gravity, pressure and velocity head
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The Correct Option is C

Approach Solution - 1

According to Bernoullis theorem, in case of steady flow of incompressible and non-viscous liquid through a tube of non-uniform cross-section, the sum of the pressure, the potential energy per unit volume and the kinetic energy per unit volume is same at every point in the tube, i.e.,
$ P+\rho gh+\frac{1}{2}\rho {{v}^{2}}=\text{constant} $
Dividing this expression by
$ \rho g, $ we have $ \frac{P}{\rho g}+\frac{{{v}^{2}}}{2g}+h=\text{constant} $
In this expression $ \frac{P}{\rho g} $
is called the pressure head, $ \frac{{{v}^{2}}}{2g} $
the velocity head and $ h $ the gravitational head.
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Approach Solution -2

According to Bernoulli's Theorem, it is a sum of the pressure head, gravitational head, and velocity head.

\(\frac{P}{\rho g}+\frac{{{v}^{2}}}{2g}+h=\text{constant}\)

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Concepts Used:

Bernauli Theorem

In fluid dynamics, Bernoulli's principle states that an increase in the speed of a fluid occurs simultaneously with a decrease in static pressure or a decrease in the fluid's potential energy. The principle is named after Daniel Bernoulli who published it in his book Hydrodynamica in 1738.

Bernaulli's Theorem