Question:
Acceleration due to gravity is $ g $ on the surface of the earth. Then the value of the acceleration due to gravity at a height of $ 32\, km $ above earths surface is: (Assume radius of earth to be 6400 km)
Acceleration due to gravity is $ g $ on the surface of the earth. Then the value of the acceleration due to gravity at a height of $ 32\, km $ above earths surface is: (Assume radius of earth to be 6400 km)
Updated On: Jan 18, 2023
- 0.99 g
- 0.8 g
- 1.01 g
- 0.9 g
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The Correct Option is A
Solution and Explanation
$ g=\frac{g}{{{\left( 1+\frac{h}{{{R}_{e}}} \right)}^{2}}}=\frac{g}{{{\left( 1+\frac{32}{6400} \right)}^{2}}}=0.99\,g $
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Concepts Used:
Gravitation
In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.
Newton’s Law of Gravitation
According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,
- F ∝ (M1M2) . . . . (1)
- (F ∝ 1/r2) . . . . (2)
On combining equations (1) and (2) we get,
F ∝ M1M2/r2
F = G × [M1M2]/r2 . . . . (7)
Or, f(r) = GM1M2/r2
The dimension formula of G is [M-1L3T-2].