Question:
ABCD is a rhombus, whose diagonals intersect at E. Then \(\overrightarrow{EA}+\overrightarrow{EB}+\overrightarrow{EC}+\overrightarrow{ED}\) equals to :
ABCD is a rhombus, whose diagonals intersect at E. Then \(\overrightarrow{EA}+\overrightarrow{EB}+\overrightarrow{EC}+\overrightarrow{ED}\) equals to :
Updated On: Jun 13, 2024
- \(\overrightarrow{0}\)
- \(\overrightarrow{AD}\)
- \(2\overrightarrow{BC}\)
- \(2\overrightarrow{AD}\)
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The Correct Option is A
Solution and Explanation
The correct option is (A) :\(\overrightarrow{0}\).
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